[Lefty]

Ok guys, I've had a long day. I'm very frustrated with things right now. I can't get the right answer on this worth shit. I'm usually good with Geometry but I think after doing 2 quizzes this weekend and trying to solve other impossible problems it has made me retarted towards easier problems. If somebody could show me how this gets set-up that'd be great. I know some things but I want to make sure I'm on the right track. Shoot me a PM if you need more questions...

Here's the problem:

"Mitchell went into a frame-it-yourself shop. He wanted a frame 3 inches longer than it was wide. The frame he chose extended 1.5 inches beyond the picture on each side. Find the outside dimensions of the frame if the area of the unframed picture is 70 inches squared."

So far I have as the width of the outer frame being "X" and the length as "X+3" I have a picture I drew with a box inside a bigger box. (The big, outer box being the frame, and the small, inner box being the picture itself). I have the frame set up to be 1.5" wide on all sides and the area of the picture is 70 inches sq.

[Sleeper_Stang_89]

the picture is 70 sq. in... the length is 3 units bigger than the width... A = L x W... (so W = L + 3) ; 70 = L x (L+3); 70 = 7 x 10; so the deminsons are 7x10; if the frame is 1.5" past the picture then it is 3 inches wider and longer than the picture... so the deminsions of the frame is 10x13... very simple

[Safi]

PIITB?

[BWAL]

Originally Posted by safi PIITB?

and i would like to add "fukkock"

[TheGreatLouisianaRoadkill]

Ask the frame expert at the shop?

[Margarita Girl]

l x w = 70

l = w+3

(w+3) x w = 70

solve for w
add 3 for l

then add 1.5 to each for final frame

[weems]

Troy, sorry bro I haven't been able to get to those problems you sent me. It has been a very, very long day. Again, I am sorry man.

[Sleeper_Stang_89]

Originally Posted by Margarita Girl l x w = 70 l = w+3 (w+3) x w = 70 solve for w add 3 for l then add 1.5 to each for final frame

now I feel a little more confident in my answer...

[Margarita Girl]

^ weems avatar reminds me of

[JASonic]

if its 70 inches squared...its gotta be 7X10...which just happens to be 3 inches longer on one side than the other. Fancy equations aside.

[Notcho]

Tell Mitchell he is an asshole for not giving you simple dimensions in inches.

Ok, your picture surface area is 70 squared, which is 70" x 70"... A=L x W or A=B x H, whichever you prefer. So, the picture must be square...

In other words the picture fits perfectly on the top and bottom of the frame, (same height as frame) but the frame is 1.5" wider on the left and right... which makes up your 3 total inches wider.

So your 70" x 70" (for the picture) becomes 73"x70" for the perimeter of the frame...

[Lefty]

Originally Posted by weems Troy, sorry bro I haven't been able to get to those problems you sent me. It has been a very, very long day. Again, I am sorry man.

Don't worry about it bro. I figured most of them out by myself. Just took me a while

Now this is the only f***er I have left on a different assignment.

[Lefty]

Originally Posted by 89 5.0 LX Tell Mitchell he is an asshole for not giving you simple dimensions in inches. Ok, your picture surface area is 70 squared, which is 70" x 70"... A=L x W or A=B x H, whichever you prefer. So, the picture must be square... In other words the picture fits perfectly on the top and bottom of the frame, (same height as frame) but the frame is 1.5" wider on the left and right... which makes up your 3 total inches wider. So your 70" x 70" (for the picture) becomes 73"x70" for the perimeter of the frame...

Is that all I need to finish the problem? What about the 1.5" between the frame and the picture?

[Notcho]

Originally Posted by JASonic if its 70 inches squared...its gotta be 7X10...which just happens to be 3 inches longer on one side than the other. Fancy equations aside.

The square of a number is that number multiplied by itself. So 3 squared is 3 x 3, which is 9....

70" squared is 70" x 70" which is 4900", which would be the surface area of the picture. In this particular problem, however, it does not ask for the surface area of the frame, just the outside dimensions.

[unlicensed to drive]

5x14 equals 70 sq inches, so wouldn't the length end up being 8x20 now since the frame is 1.5'' longer on each side, which equals 160 square inches?

[JASonic]

Originally Posted by 89 5.0 LX The square of a number is that number multiplied by itself. So 3 squared is 3 x 3, which is 9.... 70" squared is 70" x 70" which is 4900", which would be the surface area of the picture. In this particular problem, however, it does not ask for the surface area of the frame, just the outside dimensions.

ahhhhh...I thought it was 70 square inches. I fail!

[Lefty]

Maybe there's a typo in my professors sheet...because I honestly don't think it's "70 inches sq." It has to be 70 sq. inches. That's the only thing that makes sense to me.

[Lefty]

Originally Posted by JASonic ahhhhh...I thought it was 70 square inches. I fail!

See my above post.

[Notcho]

Originally Posted by Lefty Is that all I need to finish the problem? What about the 1.5" between the frame and the picture?

The two 1.5" is on each side... add them up to get the 3" longer than the width.

The problem says nothing about the thickness of the frame itself.... seemed strange they would leave that important part out.

[unlicensed to drive]

Ok, I'll explain it in more depth.

5 inches= the width of the picture 14 inches= the length of the picture.


The frame is 1.5 inches longer than the picture on each side, so you add 3 inches to both the length and the width right? Or is it just add 1.5 inches to length/width for the frame?

If I am correct, then you end up with 8x17. You now add 3 inches to the length because the frame is 3 inches longer than the width, so you end up with 8x20, resulting in an area of 160 square inches.


This is my guess.