Need some math help.

HMUSN · November 21st, 2010, 10:05 PM

My mother is in college as well and I took this course a while back and don't really remember squat about it.

It is about finding the point of an intersection given 2 points using algebraic approach.

Here are the problems. If you could break one down to me MM style I would appreciate it. Thanks.

1) 3x +4y=20 5x+4y=12
2) 4x +4y=20 3x-2y= -10
3) 2x+3y=12 4x+6x= 14

I learned it a completely different way, and with her notes I can't understand the way her teacher wants her to show the work.

Thanks again math gurus.

graystang01 · November 21st, 2010, 10:07 PM

Ugh... I haven't been in a math class in about 2 years. I vaguely remember how to do this. Hopefully someone can help you.

HMUSN · November 21st, 2010, 10:09 PM

Tell me about it. I mean I can look at it for a sec and tell the points of intersection, I just forgot how to do the breakdown is all.

BWAL · November 21st, 2010, 10:10 PM

your mom goes to college

HMUSN · November 21st, 2010, 10:13 PM

She sure does.

nawagner · November 21st, 2010, 10:38 PM

Solve each equation for y (slope-intercept form) then set each of the slope intercept equations equal to each other with only x terms, solve for x then sub x into either of the original equations to find y.

maxgst · November 21st, 2010, 11:05 PM

yeah just make the equations in each line equal to the same variable and then equal to each other:
3x+4y=20 5x+4y=12
4y=20-3x 4y=12-5x
y=5-3/4x y=3-5/4x

5-3/4x=3-5/4x
2=-2/4x
-4=x
plug into original
3(-4)+4y=20
-12+4y=20
4y=32
y=8

i hope I didnt make any mistakes, but you get the idea

carney · November 21st, 2010, 11:10 PM

Originally Posted by HMUSN

My mother is in college as well and I took this course a while back and don't really remember squat about it.

It is about finding the point of an intersection given 2 points using algebraic approach.

Here are the problems. If you could break one down to me MM style I would appreciate it. Thanks.

1) 3x +4y=20 5x+4y=12
1.First Solve get y by its self on one side
so y=-3/4x+5
2.Substitue the first equation into the second one, so 5x+4(-3/4x+5)=12
3.Solve for x, x=-4
4.Plug in 4 for x in your first eguation, so y=-3/4(-4)+5
5. Solve for y, y=8
6. point of intersection is (-4,8)
2) 4x +4y=20 3x-2y= -10
3) 2x+3y=12 4x+6x= 14

I learned it a completely different way, and with her notes I can't understand the way her teacher wants her to show the work.

Thanks again math gurus.

Your gonna wanna do the same thing for the other two, i just don't have time to do them

atlacatl213 · November 21st, 2010, 11:56 PM

you are both correct!

solve for Y in one equation, plug it in the other. Then use that X value to plug in back to the original given equation from the equation before you solved for Y to find the corresponding Y value.

November 21st, 2010, 10:05 PM	#1
HMUSN Doc 1986 SVO 48.47@ 12.58 Join Date: Nov 2006 Posts: 37,050 iTrader: 11 reviews	Need some math help. My mother is in college as well and I took this course a while back and don't really remember squat about it. It is about finding the point of an intersection given 2 points using algebraic approach. Here are the problems. If you could break one down to me MM style I would appreciate it. Thanks. 1) 3x +4y=20 5x+4y=12 2) 4x +4y=20 3x-2y= -10 3) 2x+3y=12 4x+6x= 14 I learned it a completely different way, and with her notes I can't understand the way her teacher wants her to show the work. Thanks again math gurus. __________________

November 21st, 2010, 10:09 PM	#3
HMUSN Doc 1986 SVO 48.47@ 12.58 Join Date: Nov 2006 Posts: 37,050 iTrader: 11 reviews	Tell me about it. I mean I can look at it for a sec and tell the points of intersection, I just forgot how to do the breakdown is all. __________________

November 21st, 2010, 10:10 PM	#4
BWAL MSTRB8N & MDR8N 2021 Mustang V15 Quad Turbo with nawz Join Date: Nov 2006 Location: On The Shaft Posts: 19,662 Blog Entries: 2 iTrader: 4 reviews	your mom goes to college __________________ MM 1 am boner crew Cars and mod list in garage i like veiny meat sliding between my buttcheeks

November 21st, 2010, 10:13 PM	#5
HMUSN Doc 1986 SVO 48.47@ 12.58 Join Date: Nov 2006 Posts: 37,050 iTrader: 11 reviews	She sure does. __________________

November 21st, 2010, 11:05 PM	#7
maxgst Hardcore Enthusiast 2000 Mustang GT Join Date: Jun 2010 Location: Miami, Fl Posts: 2,392 iTrader: 1 reviews	yeah just make the equations in each line equal to the same variable and then equal to each other: 3x+4y=20 5x+4y=12 4y=20-3x 4y=12-5x y=5-3/4x y=3-5/4x 5-3/4x=3-5/4x 2=-2/4x -4=x plug into original 3(-4)+4y=20 -12+4y=20 4y=32 y=8 i hope I didnt make any mistakes, but you get the idea __________________ .............................2000 GT Vert............................. How To Cut/Remove springs

November 21st, 2010, 10:38 PM	#6
nawagner Newbie 2006 Roush Sport Join Date: Aug 2010 Location: IA Posts: 27 iTrader: 0 reviews	Solve each equation for y (slope-intercept form) then set each of the slope intercept equations equal to each other with only x terms, solve for x then sub x into either of the original equations to find y.

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