HELP!! FAST PLZ SOME1!! math test tomorrow!!
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Old October 31st, 2007, 09:47 PM   #1
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HELP!! FAST PLZ SOME1!! math test tomorrow!!


i dont understand the inequalities thingy (algebra)

some1 knows plz??
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Old October 31st, 2007, 09:49 PM   #2
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solving 2 inequalities by elimination?


come on there has to b some1 that knows...

plz plz plz

if u want exercises i'l give some
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Old October 31st, 2007, 09:54 PM   #3
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post some up. always like a little refresher. lol
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Old October 31st, 2007, 10:00 PM   #4
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4x + 3y = 4
2x - y = 7
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Old October 31st, 2007, 10:02 PM   #5
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and thats one exercise u have to substitute and eliminate and i dont remember anything more...

ahh.. i tho the fucking test was next week until my girl ask me if i studied
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Old October 31st, 2007, 10:10 PM   #6
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Originally Posted by El_Cangri
4x + 3y = 4
2x - y = 7

y = 2x - 7

therefore you substitute it in the top equation

4x + 3(2x -7) = 4 now solve for x
4x + 6x - 21 = 4

10x = 25

x = 5/2

now find y by plugging in x

2(5/2) - y = 7
5 - y = 7
- y = 2
y = -2

answer: (5/2, -2)
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Old October 31st, 2007, 10:11 PM   #7
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i actually got the answer wrong i think lol but same concept
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Old October 31st, 2007, 10:15 PM   #8
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yes its the same concept

something wrong with the steps..

but its something like it.. thanx.. i'm with the book trying to figure it out..

u help me a lot since the freaking book doesnt have good examples
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Old October 31st, 2007, 10:19 PM   #9
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I cn't comprehend this... the alcohol is getting to me
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Old October 31st, 2007, 10:20 PM   #10
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all this shit is confusing
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Old October 31st, 2007, 10:35 PM   #11
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take one of the equations and solve for a single variable (whether it be the x or the y). in this case it is easier to solve for the y of the second equation. So:

2x-y=7
2x=7+y
2x-7=y

the sub y into the other equation and solve for x

4x+3(2x-7)=4
4x+6x-21=4
10x=25
x=2.5

then sub the value of x back into the equation to solve for y

2(2.5)-y=7
5-y=7
-y=2
y=-2

so X=2.5 and Y=-2
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Old October 31st, 2007, 10:50 PM   #12
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Originally Posted by GTsetGO
take one of the equations and solve for a single variable (whether it be the x or the y). in this case it is easier to solve for the y of the second equation. So:

2x-y=7
2x=7+y
2x-7=y

the sub y into the other equation and solve for x

4x+3(2x-7)=4
4x+6x-21=4
10x=25
x=2.5

then sub the value of x back into the equation to solve for y

2(2.5)-y=7
5-y=7
-y=2
y=-2

so X=2.5 and Y=-2
+1 dead on
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Old October 31st, 2007, 11:29 PM   #13
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Originally Posted by El_Cangri
4x + 3y = 4
2x - y = 7
another way to do it.. besides just substituting is to add/subtract the equations.

IE-

4x + 3y = 4
2x - y =7

Well, lets find x first.

Multiply the 2nd equation by 2 to make them both have 4x.

2(2x - y = 7)
=
4x - 2y = 14

then subtract that from the first equation-

4x + 3y = 4
- 4x - 2y = 14
5y = -10
y = -2

then substitute the y in any of the equations..
2x - y =7
2x - (-2) = 7
2x = 5
x=2.5
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Old November 1st, 2007, 12:57 AM   #14
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math

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Old November 1st, 2007, 01:03 AM   #15
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Originally Posted by 06RedfireGT
math

+1
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Old November 1st, 2007, 01:08 AM   #16
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Originally Posted by Onemanzu
Originally Posted by 06RedfireGT
math

+1
+23472347

math > me
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Old November 1st, 2007, 01:16 AM   #17
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Old November 1st, 2007, 01:42 AM   #18
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I'm so glad i'm done with math! Finished that crap my second year in college.
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Old November 1st, 2007, 01:43 AM   #19
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so i guess i did get the answer right

then 2 other people after me tried looking cool by re-writing what i did a little
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Old November 1st, 2007, 01:44 AM   #20
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Originally Posted by Jucostud
I'm so glad i'm done with math! Finished that crap my second year in college.
all i got is 106 next term and im done for ever
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